Question

Write the first four terms of the sequence whose general term is given.
an = 3n+2

Answer 1

5,8,11,14.

Explanation:

The general term of the sequence is given by :

`a_n=3n+2`

We need to find the first four terms of the sequence.

Put n = 1

`a_1=3(1)+2=5`

Put n = 2

`a_2=3(2)+2=8`

Pu n = 3

`a_3=3(3)+2=11`

Put n = 4

`a_4=3(4)+2=14`

Hence, the first four terms of the sequence are 5,8,11,14.