Question

4. Han's younger sister is riding her tricycle in a straight line. After 3 s, her speed is 0.5 m/s. After 5 s, her speed is 1.5 m/s. What is her acceleration during this time?

Answer 1

0.5 m/s ²

Explanation:

a = 1.5 m/s - 0.5 m/s = 1 m/s = 0.5 m/s ²

⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻ ⁻⁻⁻⁻⁻⁻⁻⁻

2 s 2 s

5s - 3s = 2s

1.5 m/s - 0.5 m/s = 1 m/s

1 m/s ÷ 2s = 0.5 m/s ²

Answer 2

Han's younger sister accelerated at a rate of 0.5 meters per square second during that time.

Explanation:

Let suppose that Han's younger sister accelerates at constant rate, then, acceleration (
`a`), measured in meters per square second, can be calculated by the following equation:

`a = (v_(f)-v_(o))/(t_(f)-t_(o))`

Where:

`t_(o)`,
`t_(f)` - Initial and final times, measured in seconds.

`v_(o)`,
`v_(f)` - Initial and final speeds, measured in meters per second.

If we know that
`t_(o) = 3\,s`,
`t_(f) = 5\,s`,
`v_(o) = 0.5\,(m)/(s)` and
`v_(f) = 1.5\,(m)/(s)`, the acceleration of the younger sister is:

`a = (1.5\,(m)/(s)-0.5\,(m)/(s) )/(5\,s-3\,s)`

`a = 0.5\,(m)/(s^(2))`

Han's younger sister accelerated at a rate of 0.5 meters per square second during that time.