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A car with an initial speed of 20 m/s accelerates at a uniform rate of 1.00 m/s2for 3.6 seconds. Find the speed and the displacement of the car during this time.

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Answer:

v = 23.6 m/s

d = 78.48 m

Step-by-step explanation:

Given that,

The initial speed of a car is 20 m/s

Acceleration of the car is 1 m/s²

Time, t = 3.6 s

We need to find the speed and the displacement of the car during this time.

Let v is the speed of the car. So,


v=u+at\\\\v=20+1* 3.6\\\\v=23.6\ m/s

Let d is the displacement of the car. It can be calculated as follows :


d=(v^2-u^2)/(2a)\\\\d=((23.6)^2-(20)^2)/(2* 1)\\\\d=78.48\ m

Hence, the speed and the displacement of the car during this time is 23.6 m/s and 78.48 m respectively.

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