Answer:
v = 23.6 m/s
d = 78.48 m
Step-by-step explanation:
Given that,
The initial speed of a car is 20 m/s
Acceleration of the car is 1 m/s²
Time, t = 3.6 s
We need to find the speed and the displacement of the car during this time.
Let v is the speed of the car. So,
![v=u+at\\\\v=20+1* 3.6\\\\v=23.6\ m/s](https://img.qammunity.org/2021/formulas/physics/high-school/bcc4mx5w9kcvxnp6zi9ur33o8ssyo517zc.png)
Let d is the displacement of the car. It can be calculated as follows :
![d=(v^2-u^2)/(2a)\\\\d=((23.6)^2-(20)^2)/(2* 1)\\\\d=78.48\ m](https://img.qammunity.org/2021/formulas/physics/high-school/7drl5cktv94w35xqcf3i3cmd523p9mhrwo.png)
Hence, the speed and the displacement of the car during this time is 23.6 m/s and 78.48 m respectively.