121k views
3 votes
A train is traveling with a speed of 50 miles/h with respect to the ground in the positive x-direction. A baseball player standing at the rear of the train pitches a baseball with a speed of 50 miles/h relative to the train off the back end, in the direction opposite the motion of the train. You are standing on the ground, observing the baseball. What is the velocity of the baseball at the moment of the throw that you observe

1 Answer

3 votes

Answer:

v = 0

Step-by-step explanation:

This is a relative velocity exercise, using the Galilean transformation

v = v₁ + v '

where v₁ is the speed of the object with respect to the mobile system, v' the speed of the mobile system and v the speed of the object with respect to the fixed system.

We can also write this expression with subscripts

v_at = v_am + v_mt

where v_at velocity with respect to the ground

v_am speed respecting the mobile system

v_mt velocity of the mobile system with respect to the earth

System a mobile is the train with speed v ’= 50 mile / h

the speed of the ball with respect to the mobile system is v = - 50 mile / h

the velocity of the ball with respect to the fixed system is

v = 50 -50

v = 0

User AaronJAnderson
by
8.3k points