Answer:
The value
![P(F\ n \ J) = 0.05](https://img.qammunity.org/2021/formulas/mathematics/college/bidcey22m0oavlfcz323rj1mbk994vt88z.png)
The answer is No
Explanation:
From the question we are told that
The probability a person is a jogger is
![P(J) = 21.9 \% = 0.219](https://img.qammunity.org/2021/formulas/mathematics/college/phia8byz3sg9k9dc9z2mqp6fvk7hurjgt3.png)
The probability that a person is female given that she jogs is
![P(F|J) = 21.9 \% = 0.219](https://img.qammunity.org/2021/formulas/mathematics/college/nftsynj9iwdxu4s518os9h33agfewmj4h9.png)
Generally the probability that a randomly selected person aged 20 years or older is female and jogs? Would it be unusual to randomly select a person aged 20 years or older who is female and jogs is mathematically represented as
![P(F\ n \ J) = P(J)* P(F|J)](https://img.qammunity.org/2021/formulas/mathematics/college/io2wksc3lzd0m8nsi35c60vn1e06hipakq.png)
=>
![P(F\ n \ J) = 0.219* 0.219](https://img.qammunity.org/2021/formulas/mathematics/college/esu1xfzydpiryifd02o5w267wmyy8tka6u.png)
=>
![P(F\ n \ J) = 0.05](https://img.qammunity.org/2021/formulas/mathematics/college/bidcey22m0oavlfcz323rj1mbk994vt88z.png)
Given that the probability is equal to 0.05 then it is not unusual