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What is the equation of the line that passes through the point (2,5) and has a slope of 5?

User Moritzpflaum
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1 Answer

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28 votes

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\diamond\large\textsf{\textbf{\underline{\underline{Question:-}}}}\diamond

What is the equation of the line that passes through the point (2, 5) and has a slope of 5?


\diamond\large\blue\textsf{\textbf{\underline{\underline{Answer and How to Solve:-}}}}\diamond

First let's write the equation of the line in point-slope form:-


\sf{y-y_1=m(x-x_1)}

Substitute 5 for y₁, 5 for m and 2 for x₁:-


\sf{y-5=5(x-2)}

That's the equation of the line in Point-slope form.

Now let's convert it into slope-intercept:-


\sf{y-5=5x-10}

Adding 5 to both sides results in our slope intercept equation, which looks like this:-


\dashrightarrow\bigstar\boxed{\boxed{\bold{\underline{y=5x-5}}}}\bigstar\dashleftarrow

Good luck.

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User Kenwen
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