Question

In an experiment a spot 1.0 cm in diameter contains about 12 microleters of solution. If the Fe(NO3)3 solution contains about 6.0 g Fe3+ per liter how many nanograms of Fe3+ ions are there in a 1.0 cm diameter spot og Fe(NO3)3

Answer 1

The mass of
`Fe^(3+)` present is
`x = 7.2 *10^(4) \ ng`

Step-by-step explanation:

From the question we are told that

The diameter of the spot is
`d = 1.0 \ cm`

The volume of the solution present is
`v = 12 \mu L = 12 *10^(-6) \ L`

The mass of
`Fe^(3+)` ions in one liter of solution is
`m_f = 6.0 \ g`

Generally the mass of
`Fe^(3+)` ions present is v is mathematically represented as

`x = (v * m_f)/( 1)`

`x = (12 *10^(-6) * 6)/(1)`

`x = 7.2*10^(-5) \ g`

Converting to nanograms

We have

`x = 7.2*10^(-5) \ g = ( 7.2*10^(-5))/(1 *10^(-9)) = 7.2 *10^(4) \ ng`