Answer:
Step-by-step explanation:
Acceleration acts for 9 s and deceleration acts for 12 - 9 = 3 s.
Total distance covered = 990 m
initial velocity u = o
Distance covered while accelerating
s₁ = 1/2 a 9² where a is the acceleration
= 40.5 a
final velocity after 9 s
v = at = 9a
while decelerating
v² = u² - 5 x s₂
0 = (9a)² - 5 s₂
s₂ = 16.2 a²
Distance covered while decelerating = 16.2 a²
s₁ + s₂ = 990
40.5 a + 16.2 a² = 990
16.2 a² + 40.5 a - 990 = 0
a = 6.5