Answer:
(a) The height of the cliff is 19.6 m
(b) The horizontal distance travelled by the ball is 60 m
Step-by-step explanation:
Given;
initial horizontal velocity of the ball, u = 30 m/s
initial vertical velocity of the ball, v = 0
time taken for the ball to hit the ground, t = 2 s
(a) height of the cliff
h = vt + ¹/₂gt²
h = 0 + ¹/₂gt²
h = ¹/₂gt²
h = ¹/₂(9.8)(2)²
h = 19.6 m
(b) horizontal distance traveled by the ball = Range
Range = ut
Range = 30 (2)
Range = 60 m