144k views
2 votes
3/8x + 6(x+3) = -5(1/4x - 1) + 6x find the solution pls

User Ragulka
by
7.7k points

1 Answer

4 votes

Answer:

x = -8

Explanation:

Solve for x:

(3 x)/8 + 6 (x + 3) = 6 x - 5 (x/4 - 1)

Hint: | Put the fractions in x/4 - 1 over a common denominator.

Put each term in x/4 - 1 over the common denominator 4: x/4 - 1 = x/4 - 4/4:

(3 x)/8 + 6 (x + 3) = 6 x - 5 x/4 - 4/4

Hint: | Combine x/4 - 4/4 into a single fraction.

x/4 - 4/4 = (x - 4)/4:

(3 x)/8 + 6 (x + 3) = 6 x - 5(x - 4)/4

Hint: | Put the fractions in (3 x)/8 + 6 (x + 3) over a common denominator.

Put each term in (3 x)/8 + 6 (x + 3) over the common denominator 8: (3 x)/8 + 6 (x + 3) = (3 x)/8 + (48 (x + 3))/8:

(3 x)/8 + (48 (x + 3))/8 = 6 x - (5 (x - 4))/4

Hint: | Combine (3 x)/8 + (48 (x + 3))/8 into a single fraction.

(3 x)/8 + (48 (x + 3))/8 = (3 x + 48 (x + 3))/8:

(3 x + 48 (x + 3))/8 = 6 x - (5 (x - 4))/4

Hint: | Distribute 48 over x + 3.

48 (x + 3) = 48 x + 144:

(48 x + 144 + 3 x)/8 = 6 x - (5 (x - 4))/4

Hint: | Group like terms in 48 x + 3 x + 144.

Grouping like terms, 48 x + 3 x + 144 = (3 x + 48 x) + 144:

((3 x + 48 x) + 144)/8 = 6 x - (5 (x - 4))/4

Hint: | Add like terms in 3 x + 48 x.

3 x + 48 x = 51 x:

(51 x + 144)/8 = 6 x - (5 (x - 4))/4

Hint: | Put the fractions in 6 x - (5 (x - 4))/4 over a common denominator.

Put each term in 6 x - (5 (x - 4))/4 over the common denominator 4: 6 x - (5 (x - 4))/4 = (24 x)/4 - (5 (x - 4))/4:

(51 x + 144)/8 = (24 x)/4 - (5 (x - 4))/4

Hint: | Combine (24 x)/4 - (5 (x - 4))/4 into a single fraction.

(24 x)/4 - (5 (x - 4))/4 = (24 x - 5 (x - 4))/4:

(51 x + 144)/8 = (24 x - 5 (x - 4))/4

Hint: | Distribute -5 over x - 4.

-5 (x - 4) = 20 - 5 x:

(51 x + 144)/8 = (24 x + 20 - 5 x)/4

Hint: | Combine like terms in 24 x - 5 x + 20.

24 x - 5 x = 19 x:

(51 x + 144)/8 = (19 x + 20)/4

Hint: | Make (51 x + 144)/8 = (19 x + 20)/4 simpler by multiplying both sides by a constant.

Multiply both sides by 8:

(8 (51 x + 144))/8 = (8 (19 x + 20))/4

Hint: | Cancel common terms in the numerator and denominator of (8 (51 x + 144))/8.

(8 (51 x + 144))/8 = 8/8×(51 x + 144) = 51 x + 144:

51 x + 144 = (8 (19 x + 20))/4

Hint: | In (8 (19 x + 20))/4, divide 8 in the numerator by 4 in the denominator.

8/4 = (4×2)/4 = 2:

51 x + 144 = 2 (19 x + 20)

Hint: | Write the linear polynomial on the left hand side in standard form.

Expand out terms of the right hand side:

51 x + 144 = 38 x + 40

Hint: | Move terms with x to the left hand side.

Subtract 38 x from both sides:

(51 x - 38 x) + 144 = (38 x - 38 x) + 40

Hint: | Combine like terms in 51 x - 38 x.

51 x - 38 x = 13 x:

13 x + 144 = (38 x - 38 x) + 40

Hint: | Look for the difference of two identical terms.

38 x - 38 x = 0:

13 x + 144 = 40

Hint: | Isolate terms with x to the left hand side.

Subtract 144 from both sides:

13 x + (144 - 144) = 40 - 144

Hint: | Look for the difference of two identical terms.

144 - 144 = 0:

13 x = 40 - 144

Hint: | Evaluate 40 - 144.

40 - 144 = -104:

13 x = -104

Hint: | Divide both sides by a constant to simplify the equation.

Divide both sides of 13 x = -104 by 13:

(13 x)/13 = (-104)/13

Hint: | Any nonzero number divided by itself is one.

13/13 = 1:

x = (-104)/13

Hint: | Reduce (-104)/13 to lowest terms. Start by finding the GCD of -104 and 13.

The gcd of -104 and 13 is 13, so (-104)/13 = (13 (-8))/(13×1) = 13/13×-8 = -8:

Answer: x = -8

User Simon Vane
by
9.0k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories