Question

NEED HELP ASAP PLEASE What is the area of a rectangle with a length of 3xy and a width of 14x^2y

Answer 1

`\boxed{ \bold{ \huge{ \boxed{ \sf{42 {x}^(3) {y}^(2) }}}}}`

Explanation:

`\star{ \text{ \: Length \: of \: a \: rectangle \: ( \: l \: ) \: = \: 3xy}}`

`\star{ \sf{ \: Width \: of \: a \: rectangle \: ( \: w \: ) = 14 {x}^(2)y}}`

`\underline{ \sf{Finding \: the \: area \: of \: a \: rectangle \: }}`

`\boxed{ \sf{Area \: of \: a \: rectangle = length \: \: * \: width}}`

`\dashrightarrow{ \sf{Area \: of \: a \: rectangle = 3xy * 14 {x}^(2) y}}`

`\text{Step \: 1 \: : Multiply \: the \: numbers \: and \: variables \: separately}`

`\dashrightarrow{ \sf{ (3 * 14) \: * \: x \: * \: {x}^(2) \: * \: y \: * \: y}}`

`\dashrightarrow{ \sf{42 * \: x \: * \: {x}^(2) \: * \: y \: * \: y}}`

`\text{step \: 2 \: : Add \: the \: power \: of \: the \: variables \: with \: same \: base.}`

`\dashrightarrow{ \sf{42* {x}^(1 + 2) \: * \: {y}^(1 + 1) }}`

`\dashrightarrow{ \sf{42 {x}^(3) {y}^(2) }}`

The area of a rectangle = 42 x³ y²

`\text{Hope \: I \: helped!}`

`\text{Best \: wishes!}`

~
`\text{TheAnimeGirl}`