Question

suppose that glucose concentration in a red blood cell is 0.5mm and the concentration outside of the cell is 5 mm calculate the free energy change

Answer 1

Change in free energy (ΔG) = 1.43 kcal/mol

Step-by-step explanation:

Free energy is the energy released by a diffusing molecule moving up or down a concentration gradient, across a membrane.

The formula for free energy change import into a membrane is given by the formula :

`\triangle G = \triangle G^0 + R * T * In([X]_(inside))/([X]_(outsdie))`

where:

`\triangle G = change\ in\ free\ energy\\\triangle G^0 = initial\ charge\ on molecule = 0 (Glucose\ molecule\ is\ uncharged)\\R = gas\ constant\ = 2 (cal/mol.K)\\T =Absolute\ temperature= \ ^oK = ^oC + 273 = 37 + 273 = 310\ ^oK (Note: body\ temperature\ = 37^oC)\\In = Natural\ logarithm\\`

`[X]_(inside) = concentration\ of\ glucose\ inside\ the\ cell = 0.5mM\\ {[X]}_(outside) = concentration\ of\ glucose\ outside\ the\ cell = 5mM`

`\triangle G = 0 + (2) * (310) * In([0.5])/([5]) \\\triangle G = 620 * In (0.1)\\\triangle G = 620 * (-2.3)\\\triangle G = -1426\ cal/mol\\\triangle G = 1.43\ kcal/mol`