146k views
3 votes
If AC=3x, AB=15, and BC=2x-1, how could we solve for x?

A. Set 3x=15

B. Set 3x=2x-1

C. Set 3x+15=2x-1

D. Set 3x=15+(2x-1)

E. Not enough information

User Lorenzoid
by
7.7k points

1 Answer

4 votes

Answer:

A. 3x = 15

or, x = 15/3

or, x = 5

B. 3x = 2x-1

or, 3x-2x = -1

or, x = -1

C. 3x+15 = 2x-1

or, 3x-2x = -1-15

or, x = -16

D. 3x = 15+(2x-1)

or, 3x = 15+ 2x-1

or, 3x-2x = 14

or, x = 14

User Josliber
by
8.9k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories