Answer:
The statement that describes a situation that can be modeled as a growth or decay over equal interval is;
C. A species of fly doubles its population every month during the summer
Explanation:
We have for exponential growth or decay, the following equation;
Exponential growth or decay;
![y = a \cdot b^t](https://img.qammunity.org/2021/formulas/mathematics/high-school/rjwu36lqeqj1h6ufk94dq0z10is7v3fgdc.png)
Where;
a = The initial amount of the item
1 + r = The rate of growth in percentage
b = The growth or decay factor
t = The time
For exponential decay, we have;
0 < b < 1
b = 1 - r
![y = a \cdot(1 - r)^t](https://img.qammunity.org/2021/formulas/mathematics/high-school/y6a5qz3yjf7gkczi1chriwaipqx8v39bes.png)
For exponential growth, we have;
b > 1
b = 1 + r
![y = a \cdot(1 + r)^t](https://img.qammunity.org/2021/formulas/mathematics/high-school/8evfio0vdzk7ite0kpvtpeukthnoczptcs.png)
Therefore, given that the number of the fly population doubles every month, we have the growth rate, r as 100%, which is written as 100/100 = 1, to give;
![y = a \cdot(1 + 1)^t = a \cdot(2)^t](https://img.qammunity.org/2021/formulas/mathematics/high-school/e0min0ygp3kyb4qs0cxqouwfzvoc759qq4.png)
Which is expressed as an exponential growth by an equal factor of, r, over equal intervals of, t, time.