Question

Describe the steps of constructing a segment that is TWICE as long as the given segment BD.

Answer 1

See below

Explanation:

From the segment BD, I will consider the point B as the begin and D as the end of the vector, therefore
`\overrightarrow{BD} = \vec{v}`

Once you want a segment that is twice as long as the given segment, we may say that the magnitude of the vector is

`||2\vec{v} || = √((2x)^2 + (2y)^2) = \boxed{ √(4x^2 + 4y^2) }`

Note: I'm assuming
`\vec{v} \in E^2`, which means the segment is in the plain.