Question

ICE

OC
TINITIAL
37°C
MWATER
231g
Heat will flow from the warm water into the 0° C ice.
Energy will flow until all of the ice has become water
and has the same temperature as the original warm
water, Tfinal. The amount of energy the warm water lost
(which is equal to the amount of energy the ice gained
in order to melt) can be calculated by the equation we
learned last week.
MICE +
MWATER
2.65 4
-22.5°C
TFINAL
AELost = MWATER * SH WATER (TINITIAL -TFINAL)
Х
Once you make this calculation you will have the
amount of energy that is needed to melt your total
mass of ice, so just divide it by the mass of ice you
melted and you will have the heat of fusion of ice
(Hfus for H,O) in Joules per gram of ice. Remember to
repeat the experiment at least one more time using a
different amount of water, a different amount of ice, and
.

Answer 1

Suppose that several objects composed of different materials are heated in the same manner. Will the objects warm up at equal rates? The answer: most likely not. Different materials would warm up at different rates because each material has its own specific heat capacity. The specific heat capacity refers to the amount of heat required to cause a unit of mass (say a gram or a kilogram) to change its temperature by 1°C. Specific heat capacities of various materials are often listed in textbooks. Standard metric units are Joules/kilogram/Kelvin (J/kg/K). More commonly used units are J/g/°C. Use the widget below to view specific heat capacities of various materials. Simply type in the name of a substance (aluminum, iron, copper, water, methanol, wood, etc.) and click on the Submit button; results will be displayed in a separate window.

Step-by-step explanation: