Question

9x^2 - 16 = (px+t)(px-t) both p and t are constants. Which of the following could be the value of p

Answer 1

p = 3

Explanation:

9x² - 16 ← is a difference of squares and factors in general as

a² - b² = (a + b)(a - b)

Thus

9x² - 16

= (3x)² - 4²

= (3x + 4)(3x - 4)

Compare with (px + t)(px - t)

then p = 3