Question

TOPIC: similtaneous linear equations

p1 + 2q = 3,
p - 2q = 3

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Answer 1

p = 3 ; q = 0

Explanation:

In this linear pair of eqn. in 2 variables , they have a unique solution i.e. they will have only single solution . We know that

`p + 2q=3` & also
`p -2q=3` . So, we can also equate them as :-

`p + 2q = p-2q` (∵ Both the eqn. have 3 in their right hand side product )

Solving the eqn. gives,

`=> 2q + 2q = p-p\\=> 4q=0\\=>q=0`

Putting the value of q in any one of the linear eqn gives ,

`p+2q=3\\=> p+2(0)=3\\=>p+0=3\\=>p=3`

Answer 2

q-0

p-3

Explanation:

there are two ways to solve elimination or substitution method I'll use the latter

so take the second equation and find an expression equal to p

p-2q=3

p=2q+3

substitute the above expression in the first equation

(2q+3)1+2q=3

open brackets

2q+3+2q=3

collect like terms

4q+3=3

solve

4q=0

q=0

substitute q in any equation you want I'll choose the second

p-(2×0)=3

p-0=3

p=3