Question

Consider this equilibrium reaction at 400 K. Br2(g)+Cl2(g)↽−−⇀2BrCl(g)Kc=7.0 If the composition of the reaction mixture at 400 K is [BrCl]=0.00415 M, [Br2]=0.00366 M, and [Cl2]=0.000672 M, what is the reaction quotient, ???? ? ????= How is the reaction quotient related to the equilibrium constant, Kc, for this reaction?

Answer 1

Q = 7.0

Q = kc. The reaction is in equilibrium

Step-by-step explanation:

Based on the reaction:

Br₂ + Cl₂ ⇄ 2BrCl

Equilibrium constant of the reaction, kc, is the ratio of equilibrium concentrations products over reactants powered to its reaction coefficient:

Kc = [BrCl]² / [Br₂] [Cl₂] = 7.0

Now, reaction quotient, Q, is write as the same Kc but the concentrations are actual concentrations:

Q = [BrCl]² / [Br₂] [Cl₂]

Replacing:

Q = [0.00415M]² / [0.00366M] [0.000672M]

Q = 7.0

Now, as Q = Kc = 7.0, the reaction mixture is in equilibrium