Question

In 1970, a farmer using a two-row combine with a corn head could easily harvest 0.75 ha (1.85 acres) per hour and a typical corn yield was 5000 kg/ha (80 bu/acre). Before 1940, most corn was harvested by hand and a skilled person could harvest 250 kg/h (10 bu/h). Calculate the productivity ratio.

Answer 1

The value is
`w = 6.7 \%`

Explanation:

Generally the productivity rate is mathematically represented as

`P_r = K * Z`

Here K is the ha the farmer could harvest in an hour and Z is a typical yield of corn in kg/ha

Now considering 1970

The productivity rate is

`P_r = 0.75 *5000`

=>
`P_r = 3750 \ kg/h`

Now considering 1940

The productivity rate is given as
`P_R = 250 \ kg/h`

Generally the productivity ratio is mathematically ration is mathematically represented as

`w = (P_R)/(P_r) * 100`

=>
`w =  (250)/(3750)  * 100`

=>
`w = 6.7 \%`