Answer:
1. See Explanation for Sample Space
2.
![P(10) = (1)/(12)](https://img.qammunity.org/2021/formulas/mathematics/college/1pha5kt7noq2r2ork55f6qr2cceftlagi0.png)
3.
![P(6) = (5)/(36)](https://img.qammunity.org/2021/formulas/mathematics/college/6zl0ilit23xg8n69u6yn77j73w1xycsg96.png)
Explanation:
Given
Roll of Two die
Solving (1): The Sample Space
Represent the first dice with S1 and the second with S2
![S_1 = \{1,2,3,4,5,6\}](https://img.qammunity.org/2021/formulas/mathematics/high-school/nsmee2fzu7gdxu8ab1os0f4p5meemsls2a.png)
![S_2 = \{1,2,3,4,5,6\}](https://img.qammunity.org/2021/formulas/mathematics/high-school/474zcdnremxvuvxknfzop4k8zq84gyq51b.png)
The sample space of both die is:
![S = (1,1)(1,2)(1,3)(1,4)(1,5)(1,6)(2,1)(2,2)(2,3)(2,4)(2,5)(2,6)(3,1)(3,2)(3,3)(3,4)(3,5)(3,6)](https://img.qammunity.org/2021/formulas/mathematics/college/81bdiq8pcidbgnyasz19ffwcmodtvaqgfg.png)
![(4,1)(4,2)(4,3)(4,4)(4,5)(4,6)(55,1)(5,2)(5,3)(5,4)(5,5)(5,6)(6,1)(6,2)(6,3)(6,4)(6,5)(6,6)}\}](https://img.qammunity.org/2021/formulas/mathematics/college/km8f39w2xjo24zs6eizy6uiawib0fdbkuv.png)
Solving (2): Probability of Sum being 10
First, we need to add the outcome of each roll in (1) above:
![S = \{2,3,4,5,6,7, 3,4,5,6,7,8, 4,5,6,7,8,9, 5,6,7,8,9,10, 6,7,8,9,10,11 7,8,9,10,11,12\}](https://img.qammunity.org/2021/formulas/mathematics/college/4jo1u2nx955fm803o38nnzww7ulwyrqtv1.png)
![n(S) = 36](https://img.qammunity.org/2021/formulas/mathematics/middle-school/6pe1a3fnxu3br4jthhm3lzcqosx81mqf3r.png)
![n(10) = 3](https://img.qammunity.org/2021/formulas/mathematics/college/uu6asf16lxadq7unsgwsgm1yqo48r5igic.png)
The required probability is:
![P(10)= (3)/(36)](https://img.qammunity.org/2021/formulas/mathematics/college/7fjzdp2r58cd8gjmp3gn25rs0ukvvgqq16.png)
![P(10) = (1)/(12)](https://img.qammunity.org/2021/formulas/mathematics/college/1pha5kt7noq2r2ork55f6qr2cceftlagi0.png)
Solving (3): Probability of Sum being 6
![n(S) = 36](https://img.qammunity.org/2021/formulas/mathematics/middle-school/6pe1a3fnxu3br4jthhm3lzcqosx81mqf3r.png)
![n(6) = 5](https://img.qammunity.org/2021/formulas/mathematics/college/v2qa2aqieoilv39d4umsdjmuxsx3lsb8gw.png)
The required probability is:
![P(6) = (5)/(36)](https://img.qammunity.org/2021/formulas/mathematics/college/6zl0ilit23xg8n69u6yn77j73w1xycsg96.png)