Question

. A certain tap can fill a tank in 4 hours and

another tap can fill it in 6 hours. If both the taps
are opened, how long will it take for the tank to
be full?​

Answer 1

Given -

• Time taken by first tap = 4 hours.
• Time taken by second tap = 6 hours.

Now, we'll calculate the work done by both the taps -

`\\ \sf \: (1)/(4) + (1)/(6) \\ \\ \\ \bf \: lcm \: \: of \: \: 4 \: \: \& \: \: 6 = 12 \\ \\ \\ \implies \sf \: (3 + 2)/(12) \\ \\ \\ \implies \sf (5)/(12) \\ \\`

Now, reciprocal it -

`\\ \implies \sf (12)/(5) = 2 (2)/(5) \\`

Therefore, time taken by both the taps will be 2 2/5 hours.