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(3x+4y=18) (5x+6y=28)​

User Meligira
by
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1 Answer

7 votes

Answer:

x = 2, y = 3

Explanation:

Given the 2 equations

3x + 4y = 18 → (1)

5x + 6y = 28 → (2)

Multiplying (1) by 5 and (2) by - 3 , then adding will eliminate the term in x

15x + 20y = 90 → (3)

- 15x - 18y = - 84 → (4)

Add (3) and (4) term by term to eliminate x

2y = 6 ( divide both sides by 2 )

y = 3

Substitute y = 3 into either of the 2 equations and solve for x

Substituting into (1)

3x + 4(3) = 18

3x + 12 = 18 ( subtract 12 from both sides )

3x = 6 ( divide both sides by 3 )

x = 2

Solution is (2, 3 )

User Ramji
by
7.8k points