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The sum of 3 consecutive integers is -69. Find the largest

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x = the first integer

x + 1 = the second integer

x + 2 = the third integer.

Let's set each of our variables equal to -69

x + x + 1 + x + 2 = -69

Combine like terms

3x + 3 = -69

Subtract 3 from both sides.

3x = -72

Divide both sides by 3

x = -24

The first integer = x = -24

The second integer = x + 1 = -24 + 1 = -23

The third Integer = x + 2 = -24 + 2 = -22

User Theowi
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