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How many grams are there in 1.00x10 24 molecules of BCI3
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How many grams are there in 1.00x10 24 molecules of BCI3

User Mahani
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1 Answer

3 votes

Answer:

194.569 g

Step-by-step explanation:

6.022×10^23 molecules = 117.17 g

1 molecules = 117.17/ 6.022×10^23

So, 1×10^24 molecules = (117.17×1×10^24)/(6.022×10^23)= 194.569 g

User Madhurgarg
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