Question

Find surface area of the regular pyramid plz help ASAP

Answer 1

= 3,157 in^2

Explanation:

surface area = 3x lateral area + base area

given:

side lengths area s1 = s2 = s3 = 42 in

slant height = 38 in

lateral area = ( 1/2 * 42 * 38 )

= 798 sq. in

base area = (√3 * s^2 ) / 4

= (√3 * 42^2 ) / 4

= 763.83 sq. in

surface area = 3x 798 + 763.834

= 3,157 in^2

Answer 2

B. 3,157 in^2

Explanation:

surface area of a pyramid shown = 3x lateral area + base area

given:

s1 = s2 = s3 = 42 in

L = 38 in

lateral area = ( 1/2 * 42 * 38 ) = 798 sq. in

base area = √3 * s^2

4

= √3 * 42^2

4

= 763.834 sq. in

therefore,

surface area of a pyramid shown = 3x 798 + 763.834 = 3,157 in^2