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What is the mass in grams of 1.9×1023 atoms of lead?

User Mario Mey
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1 Answer

4 votes

Answer:

Step-by-step explanation:

# moles that exist in 1.9 X 10 23 =

= # of atoms/# of Avogadro 's num

= 1.9 X 10 23 / 6.02x10 23

= 0.266 mole of Pb

now we calculate the mass

mass of lead = # mol x m.wt

= 0.266 X 106.4

= 28.30 gram

User Nothehi
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