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How is the graph of y = (x + 1)^2- 5 transformed from the graph of y=x^2?

User SaxonMatt
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\text{Hi there! :D}


\boxed{\text{There is a horizontal shift of 1 unit left and 5 units down.}}


\text{Recall that the transformations form of a quadratic function is:}\\\\y = \pm a(b(x-h))+k \text{ where:}\\\\a = \text{ vertical stretch/compression}\\\\b = \text{ horizontal stretch/compression}\\\\h = \text{ shift left/right}\\\\k = \text{ shift up/down}\\\\\text{Therefore, in this instance:}\\\\h = -1\\\\k = -5, \text{ so:}\\\\\text{There is a horizontal shift of 1 unit left and 5 units down.}

User Bacon Bits
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