Question

The perimeter of a rectangle is 22 inches. Find the dimensions if its length is 3 inches greater than its width.

Answer 1

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Explanation:

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Answer 2

Length: 7

Width: 4

Explanation:

We can create a system of equations for this problem, where
`w` is the width and
`l` is the length.

The perimeter of a rectangle is twice its length added to twice its width.

`2l+2w=22`

The length is 3 more than the width:

`l = w+3`

We can now substitute in
`w+3` as
`l` in the equation
`2l+2w=22`.

`2(w+3) + 2w = 22`

Distribute the first terms:

`2w+6+2w=22`

Combine like terms:

`4w+6=22`

Subtract 6 from both sides:

`4w=16`

Divide both sides by 4:

`w = 4`

Now we know that w = 4. We can now substitute this inside an equation to find
`l`.

`l = w+3\\\\l = 4+3\\\\l=7`

Hope this helped!