Question

PLEASE HELP A cylinder with radius 6 feet and height 6 feet has its radius doubled. How many times greater is the volume of the larger cylinder than the smaller​ cylinder? How many times greater is the volume of the larger cylinder than the smaller​ cylinder?

Answer 1

16 Times Greater

Explanation:

Smaller cylinder:

radius = 6 inches

height = 8 inches

area = (pi)r^2h

area = (3.14)6^2(8)

radius = 24 inches

height = 8 inches

area = (pi)r^2h

area = (3.14)24^2(8)

.

[(3.14)6^2(8)] / [(3.14)24^2(8)]

[6^2(8)] / [24^2(8)]

[6^2] / [24^2]

[36] / [576]

16 times greater

Answer 2

Explanation:

Smaller cylinder:

h = 6 ft

r = 6 ft

Volume of smaller cylinder = πr²h

= π * 6 * 6 * 6 cubic ft

Bigger cylinder:

r = 6 * 2 = 12 ft

h = 6 ft

Volume of bigger cylinder = π * 12 * 12 * 6 cubic ft

Volume of bigger cylinder = π * 12 * 12 * 6

Volume of smaller cylinder π * 6 * 6 * 6

=
`(2 * 2)/(1*1)\\`

= 4 : 1

The volume of greater cylinder is 4 times than the smaller cylinder.