Question

Please solve as fast as possible...
No spams please......​

Answer 1

In ∆ABD and ∆ACD

<BAD =<CAD ( each are half of <A )

<D=<D ( each equal to 90°)

AD = AD ( common)

So ∆ ABD is congruent to ∆ ACD.

Then AB =AC (by C.P.C.T)

Hence,∆ABC is an iso - sceles triangle.