Question

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Answer 1

Area of triangle = 1/2 × b × h

b = base and h = height

Area = 1/2 × (x+4) × (2)

Area = x + 4

Area of rectangle = lb

l = Length and b = Breadth

Area = 10 (x + 2)

Area = 10x + 20

Given:

The area of rectangle is 8 times greater than the area of the triangle.

Solution:

According to the question,

10x + 20 = 8(x+4)

or, 10x + 20 = 8x + 32

or, 10x - 8x = 32 - 20

or, 2x = 12

or, x = 12/2 = 6

Answer:

The value of x is 6.

Hence, Option D. 6 is correct.

Answer 2

x = 6

Explanation:

Area of rectangle = length * width

= 10 *(x +2)

= 10*x + 10*2

= 10x + 20 unit²

Area of triangle =
`(1)/(2)bh`

`=(1)/(2)*2*(x +4)\\\\=1*(x+4)\\\\= x +4`

Area of rectangle = 8*area of triangle

10x + 20 = 8* (x+ 4)

10x + 20 = 8x + 32 {Subrtact 20 from both sides}

10x = 8x + 32 - 20

10x = 8x + 12 {subtract 8x form both sides}

10x - 8x = 12

2x = 12 {divide both sides by 2}

2x/2 = 12/2

x = 6