Question

F(x)=9(x-8) find f^-1(x)

Answer 1

`f^(-1)`(x) =
`(1)/(9)` x + 8

Explanation:

let y = f(x) and rearrange making x the subject, that is

y = 9(x - 8) ← divide both sides by 9

`(y)/(9)` = x - 8 ( add 8 to both sides )

`(y)/(9)` + 8 = x

Change y back into terms of x with x =
`f^(-1)`(x) , thus

`f^(-1)`(x) =
`(1)/(9)` x + 8