Answer:
Let B(a,b) be x1, y1
A(-6,1) be x2,y2
midpoint M(-3,2) be (x,y)
using midpoint formula
(x,y)= [(x1+x2)/2, (y1+y2)/2)
(-3,2) = [(a-6)/2, (b+1)/2}
comparing corresponding value
-3 = (a-6)/2 (b+1)/2 = 2
-6= a-6 b+1=4
a=0 b=3
coordinates of B = (0,3)