Question

ASAP

Water flowed out of a tank at steady rate. A total of 18 1/2 gallons flowed out of a tank in 4 1/4 hours. Which expression determines the the quality of water leaving the tank per hour?
O 17/4 divide 36/2
O 36/2 divide 17/4
O 17/4 divide 37/2
O 37/2 divide 17/4

Answer 1

total galloons flowed=18 1/2=36/2

time that it flowed=4 1/4=16/4

rate=total galloons flowed/time to flow

rate=36/2÷16/4

=9/2gallons per hour

4.5gallons per hour

Answer 2

Answer: In 1 hour water flowed out = 74/17 gallons

Explanation:

Given as ,

The quantity of water flowed out of tank = 18 1/2 gallons

= 37/2 gallons

The time spend in flowing water out of tank = 4 1/4 hours

= 17/4 hours

∵ In 17/4 hours , water flowed out = 37/2

∴ In 1 hours , water flowed out =

So, in 1 hour water flowed out = 37*4/17*2 gallons Answer