Answer:
162.35 amu
Step-by-step explanation:
Let A represent isotope X-159
Let B represent isotope X-163
Let C represent isotope X-164
The following data were obtained from the question:
Isotope >>> Abundance >>> Mass no
A >>>>>>>> 30.60 >>>>>>>> 159.37
B >>>>>>>> 15.79 >>>>>>>>> 162.79
C >>>>>>>> 53.61 >>>>>>>>> 163.92
Average Atomic mass =.?
The average atomic mass of element X can be obtained as follow:
Average atomic mass = [(mass of A × A%)/100] + [(mass of B × B%)/100] + [(mass of C × C%)/100]
= [(159.37 × 30.60)/100] + [(162.79 × 15.79)/100] + [(163.92 × 53.61)/100]
= 48.77 + 25.70 + 87.88
= 162.35 amu
Therefore, the average atomic mass of element X is 162.35 amu