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Solve: 3(2x+1)-2(x-5)-5(5-2x)=16 value of x?​

1 Answer

3 votes

Answer:


\boxed{ \bold{ \huge{ \boxed{ \sf{x = 2}}}}}

Explanation:


\displaystyle{ \star{ \: \: \underline{ \sf{given \: equation}}}} :


\sf{3(2x + 1) - 2(x - 5) - 5(5 - 2x) = 16}

Distribute 3 through the parentheses


\mapsto{\sf{6x + 3- 2(x - 5)- 5(5 -2x) = 16}}

Distribute 2 through the parentheses


\mapsto{ \sf{6x + 3 - 2x + 10- 5(5 - 2x) = 16}}

Distribute 5 through the parentheses


\mapsto{ \sf{6x + 3 - 2x + 10 - 25 + 10x = 16}}

Combine ike terms and simplify it

Like terms are those which have the same base


\mapsto{ \sf{6x - 2x + 10x + 3 + 10 - 25 = 16}}


\mapsto{ \sf{4x + 10x + 3 + 10 - 25 = 16}}


\mapsto{ \sf{14x + 3 + 10 - 25 = 16}}

Add the numbers : 3 and 5


\mapsto{ \sf{14x + 13 - 25 = 16}}

The negative and positive integers are always subtracted but posses the sign of the bigger integer.


\mapsto{ \sf{14x - 12 = 16}}

Move 17 to right hand side and change it's sign


\mapsto{ \sf{14x = 16 + 12}}

Add the numbers: 16 and 17


\mapsto{ \sf{14x = 28}}

Divide both sides by 14


\mapsto{ \sf{ (14x)/(14) = (28)/(14)}}

Calculate


\mapsto{ \boxed{ \sf{x = 2}}}

The value of x is 2

Hope I helped!

Best regards!

~TheAnimeGirl

User Firemaples
by
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