We are given with the radius of the circular field,
![r = 42 \: m](https://img.qammunity.org/2021/formulas/mathematics/high-school/b47m7a7folf0m6xrvw0rve5969q0utld7h.png)
And, we have to find the perimeter of the field. Also, we have to find the length of the wire required to fence it with 5 rounds:
We know,
Perimeter of a circle = 2πr, where r is the radius of the circle, So let's find the perimeter by using this formula.
![perimeter = 2\pi r](https://img.qammunity.org/2021/formulas/mathematics/high-school/eftjgx2g83ju6y31lg0ablifbyiska1u4f.png)
![perimeter = 2 * (22)/(7) * \: 42 m](https://img.qammunity.org/2021/formulas/mathematics/high-school/rrytwkt4xcahbm7zgoec2e0yk9wic5ua30.png)
![perimeter = 2 * 22 * 6 \: m](https://img.qammunity.org/2021/formulas/mathematics/high-school/8gcmqs27wkl5iib69d3yl2uq0h4in0we2q.png)
![perimeter = \boxed{264 \: m}](https://img.qammunity.org/2021/formulas/mathematics/high-school/e57sse7ad4jwuduzrra6wcshrku8ml4uzb.png)
Now, finding the length of the wire which is equals to 5 × Perimeter of the circular field.
![length \: of \: wire = 264 \: m * 5](https://img.qammunity.org/2021/formulas/mathematics/high-school/7stkunjffmcx0se53cxnar6z1qw9af48rq.png)
![length \: of \: wire = \boxed{1320 \: m}](https://img.qammunity.org/2021/formulas/mathematics/high-school/hs6lf9ss9hlw49htxq3cms6ziojfkjjnuo.png)
And we are done !!
#CarryOnLearning.
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