Question

Can someone help me with number 7 and 8. Thank you

Answer 1

Q7) ( 2,-2)

Q8) (- 0.5 , -2)

Explanation:

As we have to find the mid-points of the line segments, the line segments will be divided in same ratio i.e. 1:1 (∵ A Mid-point divides a line segment into equal parts )

According to Section formula ,

`( x' , y') = ((mx^2 + nx^1)/(m+n) , (my^2+ny^1)/(m+n) )`

where (m,n) are the ratios in which a line segment is divided & ( x¹ , y¹ ) ( x², y²) are the co-ordinates of a line segment.

In Q7 ,

x¹ = 3 , y¹ = -9 , x² = 1 , y² = 5 & m = n = 1

So putting the section formula here gives :-

`( x' , y') = ((1*1 + 1*3)/(1+1) , (1*5+1*(-9))/(1+1) ) = ( 2 , -2)`

In Q8 ,

x¹ = 5 , y¹ = -1 , x² = -6 , y² = -3

So putting the section formula here gives :-

`(x' , y') = ((1*(-6) + 1*5)/(1+1) , (1*(-3) + 1*(-1))/(1+1)) = ( -0.5 , -2)`