Question

R = (2+2+1) i - (t+1)] + t3 k
what is the direction of initial velocity

Answer 1

In the - j direction, that is negative of the y-axis

Step-by-step explanation:

As typed in the question, the position of the object is given by the expression in three component ( i, j, k) form:

r (t) = 5 i - (t + 1 ) j + t^3 k

and since the velocity is the derivative of position with respect to time, by doing the derivative of this expression we get:

v(t) = 0 i - 1 j +3 t^2 k

which for the initial velocity requested (that is at time zero) we have:

v(t) = 0 i - 1 j +3 (0)^2 k = = 1 j

Then the direction of the initial velocity is entirely in the direction of the j versor, that is pointing to the negative of the y-axis.