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How many grams of Cl2 are in 0.345L at STP?
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How many grams of Cl2 are in 0.345L at STP?

User Fkreusch
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1 Answer

5 votes

Answer: 1.09 g

Step-by-step explanation:

If we use the approximation that 1 mole is 22.4 L, then setting up a proportion,

  • 1/22.4 = x/0.345 (x is the number of moles in the sample)
  • x = 0.0154 mol

Since the mass of a mole of chlroine is about 70.9 g/mol, (0.0154)(70.9) = 1.09 g (to 3 s.f.)

User Phil Barresi
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