Question

A scuba tank has pressure of 195 kpa at temperature 10 c the volume of the tank is 350 L how many grams of air ins in the tank?

Answer 1

`m=840.88g`

Step-by-step explanation:

Hello,

In this case, considering the ideal gas equation as:

`PV=nRT`

We can first compute the moles of air at the given conditions of 195 kPa (1.92 atm), 10 °C (283K) and 350 L:

`n=(PV)/(RT)=(1.92atm*350L)/(0.082(atm*L)/(mol*K)*283K)\\ \\n=29.03molAir`

Next, since the molar mass of air is 28.97 g/mol, the mass is computed to be:

`m=29.03mol*(28.97g)/(1mol) \\\\m=840.88g`

Best regards.