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Sun^4A+sin^2Acos^2A=sin^2A​

1 Answer

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Explanation:

sin⁴A + sin²Acos²A = sin²A

Proving the left hand side ( LHS)

That's

sin⁴A can be written as ( sin²A)(sin ²A)

So we have

( sin²A)(sin ²A) + sin²Acos²A

Next factor sin²A out

That's

sin²A ( sin²A + cos²A)

Using trigonometric identities

That's

sin²A + cos²A = 1

Simplify the expression

That's

sin²A × 1

We have the final answer as

sin²A

As proven

Hope this helps you

User Infeligo
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