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√(4/7)^2 =
equations with square roots and cube roots

√(4/7)^2 = equations with square roots and cube roots-example-1
User Josh Pinto
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2 Answers

1 vote
The answer is : 4/7
Decimal: 0.571 (Not Rounded)
User Atri
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4 votes

Answer:

See below

Explanation:

If you are squaring a number, and then taking the square root of it, you are essentially undoing the original operation:


\displaystyle \sqrt{\biggr((4)/(7)\biggr)^2}=\biggr[\biggr((4)/(7)\biggr)^2\biggr]^{(1)/(2)}=\biggr((4)/(7)\biggr)^{2*(1)/(2)}=(4)/(7)

Hence, we are back starting with the original number

User Sylma
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