Question

The sum of three consecutive multiples of 4 is 444. Find these multiples.

Answer 1

First multiple of 4 is x = 144

Second multiple of 4 is x + 4 = 144 + 4 = 148

Third multiple of 4 is x + 8 = 144 + 8 = 152

Answer 2

Explanation:

Let the first multiple of 4 be x and second multiple be (x + 4) and third multiple be (x + 8) ...[Since, the number are consecutive multiple of 4]

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`\underline{\boldsymbol{According\: to \:the\: Question\:now :}}\\`

`:\implies \sf x \: + \: x \: + \: 4 \: + \: x \: + \: 8 \: = \: 444 \\ \\ \\`

`:\implies \sf 3x \: + \: 12 \: = \: 444 \\ \\ \\`

`:\implies \sf 3x \: = \: 444 \: - \: 12 \\ \\ \\`

`:\implies \sf 3x \: = \: 432 \\ \\ \\`

`:\implies \sf x \: = \: (432)/(3) \\ \\ \\`

`:\implies\underline{ \boxed{\sf x \: = \: 144}} \\`

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Therefore,

`\bullet\:\:\textsf{First multiple of 4 = x = \textbf{144}} \\`

`\bullet\:\:\textsf{Second multiple of 4 = x + 4 = 144 + 4 = \textbf{148}} \\`

`\bullet\:\:\textsf{Third multiple of 4 = x + 8 = 144 + 8 = \textbf{152}}`