Question

`x(x^2+8)=8(x+1)`x(x^2+8)=8(x=1)

Answer 1

`x=2`

Explanation:

`x\left(x^2+8\right)=8\left(x+1\right)`

Expand:

`x* x^2+8x=8x+8* 1`

`x^3+8x=8x+8`

Subtract 8x from both sides:

`x^3+8x-8x=8x+8-8x`

`x^3=8`

Cube root both sides:

`\sqrt[3]{x^3} =\sqrt[3]{8}`

`x=2`