Question

If 5.0 g of copper cools from 35.0oC to 22.6 oC and loses 23.6 J of heat, what is the specific heat of copper? a. 0.038 J/(g. oC) b. 0.62 J/(g. oC) c. 0.076 J/(g. oC) d. 0.38 J/(g. oC)

Answer 1

c = 0.38 J/(g-°C)

Step-by-step explanation:

Given that,

Mass of copper, m = 5 g

Initial temperature,
`T_i=35^(\circ) C`

Final temperature,
`T_f=22.6^(\circ) C`

When copper cools, it looses 23.6 J of heat. We need to find the specific heat of copper. The heat lost is given by :

`Q=mc\Delta T`

c is specific heat

`c=(Q)/(m\Delta T)\\\\c=(23.6)/(5* (22.6-35))\\\\c=0.38\ J/g-^(\circ) C`

Hence, the correct option is d.