Question

How do i solve the equation
`(2a^(3) b^(4)c^(0))^(3)`

Answer 1

`8(-2x)/(-2)=(0)/(-2)`

Explanation:

`\left(2a^3b^4c^0\right)^3`

Cube each portion:

`2^3\left(a^3\right)^3\left(b^4\right)^3\left(c^0\right)^3`

`8\left(a^3\right)^3\left(b^4\right)^3\left(c^0\right)^3`

`8a^9\left(b^4\right)^3\left(c^0\right)^3`

`8a^9b^(12)\left(c^0\right)^3`

`8a^9b^(12)*1`

`8a^9b^(12)`