Answer:
![\boxed {\tt x=3}](https://img.qammunity.org/2021/formulas/mathematics/high-school/2zzbjyfc1ff5hl8qy9x6sxzruj88zvwzx2.png)
Explanation:
We are given the equation:
![5x-2=3x+4](https://img.qammunity.org/2021/formulas/mathematics/high-school/pr11agbzgvfup5uruy6vr0jfm3pi5lozzj.png)
We want to solve for x, therefore we must isolate x on one side of the equation.
First, move all the constants to one side of the equation. 2 is being subtracted from 5x. The inverse of subtraction is addition. Add 2 to both sides.
![5x-2+2=3x+4+2](https://img.qammunity.org/2021/formulas/mathematics/high-school/2sjdklis4t2yfaghg8vlhzs0874syso7si.png)
![5x=3x+4+2](https://img.qammunity.org/2021/formulas/mathematics/high-school/ii9kh8vac81xjf0nbolf9z4vgr55vwrwfs.png)
![5x=3x+6](https://img.qammunity.org/2021/formulas/mathematics/high-school/3ixr46atljy5ohzuy02q2q0nbltp2bch5e.png)
Next, move all the terms with variables to one side. 3x is being added to 6. The inverse of addition is subtraction. Subtract 3x from both sides.
![5x-3x=3x-3x+6](https://img.qammunity.org/2021/formulas/mathematics/high-school/1a80vnwvrlamnx1fy6p1zkflt80o9eminq.png)
![5x-3x=6](https://img.qammunity.org/2021/formulas/mathematics/high-school/mogkih6l8h26e4e5szfk6cfqkh1r7h8dtf.png)
![2x=6](https://img.qammunity.org/2021/formulas/mathematics/middle-school/6sesyg6t9z5pu68t33pbgi41i56b0t8uwz.png)
x is being multiplied by 2. The inverse of multiplication is division. Divide both sides of the equation by 2.
![(2x)/(2) =(6)/(2)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/bi6x16slhcivpirklvo74j1va6d95pyuek.png)
![x=(6)/(2)](https://img.qammunity.org/2021/formulas/mathematics/high-school/hvqwe703evj4c12rppt9jseoxfjxfveznk.png)
![x=3](https://img.qammunity.org/2021/formulas/mathematics/college/yzekanmiuar9edsve93wg5dpqbw3650n5b.png)
x is equal to 3 and the correct answer is D. x=3